Now, how about splitting Aces always?
Well, if you take a look in Wong�s �Professional BJ� on table # 10 (Strategy numbers for H17) and see the index numbers for splitting AA vs. 8,9,T and A, they are:
AA vs. 8 split if TC>=-8
AA vs. 9 split if TC>=-7
AA vs. T split if TC>=-8
AA vs. A split if TC>=-4
If you take a look at the index numbers for doubling down on 11 vs. 8,9,T and A, they are:
11 vs. 8 double if TC>=-6
11 vs. 9 double if TC>=-4
11 vs. T double if TC>=-4
11 vs. A double if TC>= 0
As you very well know in both cases when you split AA or you double down you get only one single card. You give up the option of any subsequent hits for the privilege of doubling your bet after seeing your cards. In both cases you are allowed to take only one card. Also, in both instances you are drawing one single card on 11. Regardless, when you have 56 vs. T for a double or A vs. T and A vs. T for a split in both instances you are drawing one card on hard 11. Further more, when you decide to split the AA you give up the option of counting the Ace =1 and automatically the Ace become hard 11. In essence you give the edge back to the house and you cannot manipulate anymore the Ace to be 1 or 11 while getting one single card when you split. But this is another subject all together.
Let�s get back and compare the two table from Wong�s book.
The table indicate that is correct for a 11 to go against the T if the TC>=-4 while drawing only one card in the case of a double down move. And, also is correct for an A=11 to go against a T if the TC>=-8 while drawing only one card in the case of split AA vs. T.
If is correct to split AA vs. T and drawing and drawing one card only on each Ace=11 in a �8 count why is not correct to double down on any 11 vs. T if the count is �8? Why the count got to be >=�4 for doubling down? In both situations we are drawing on hard 11 one single card. Are we?
The same thing happen for the other double downs or splits. We double 11 vs. A only if the count per deck is zero or positive but we split AA vs. Ace even if the count per deck is negative 4. In both instances we doing the same thing such as drawing one single card on hard 11. �., and so on �
Well, you cannot have it both ways.