Can you prove or disprove these arguments?
Here are the arguments of someone whom seems very knoledgable about the game. I will keep him anonamous because I do not want biased information and I have not obtained obtained his permission to say who it is.
Here is the info for the single deck game www.performax.biz/here
Here are the players arguments.
looked over the data. I cannot spend all of the time with it that it deserves as I am on the road playing BJ.
You have the settings for the program set up wrong. That MUST be the answer.
Firstly, I imagine that by selecting the depth that you have you have done yourself a disservice. It is NOT real. The graphs show decks being played out heads up with TEN hands played. ordinarily (on average) a hand of BJ contains 2.7 cards (5.5 cards per round heads-up) That equates to 55 cards in a single deck. So, ordinarily Ten hands in a round is impossible unless ALL the TENS have been played during those TEN hands. Furthermore, the highest and lowest true counts attained are not as extreme as they ought to be, or am I mistaken about that.
You checked "Soft DD counts as Hard Hand" Is the program allowing you to Double down on hands other than 10 or 11 ? It may be doing that, because you also checked "DD on Two Cards" - Does it interpret that as ANY two cards ?
The S.E. looks a bit large to me at .007 but it is probably not an issue here.
The T.B.A. of 0.026 and the I.B.A. is .0.024 are shown.
These figures are completely impossible because you need to first overcome the [BIG] -.40 house advantage at ZERO True Count.
You must look at the distribution of TRUE COUNTS.
The nature of the True Count with ANY Balanced Count is such that it must be both perfectly symmetrical and linear -- meaning that it is NOT possible what I am seeing in your data - e.g. where you look at the positive and negative True Counts and they are not equivalent. Thus if +3 and -3 are compared they should be very very close to the same probability of occurrence.
In the TRUE COUNT DISTRIBUTION Chart some True Counts are basically non-existent. HOW is it possible that +9 and -3 T.C.'s do not hardly ever happen ? OBVIOUSLY that simply CANNOT BE.
Look at: "Win, Loss & Tied Percentages by Hand Depth" It shows that there were ALWAYS 7 hands and only occasionally could there not be 8 hands. 9 hands happened millions of time and 10 hands happened as I mentioned before. So almost all of the time a bizarre 8 hands were played. On average that would consume 5.4 times 8 rounds = 44 cards. 44 cards of 52, which as stated above will NEVER be dealt, is equal to penetration of 85% !
Under the heading of "Miscellaneous Stats" is shows: Hands won = 49.70% Hands Lost = 49.40% Pushes = .90% Less than 1% L.O.L. That is simply ludicrous.
An interesting stat displayed is "Ran out of Cards = 4,296" Ran OUT is NOT POSSIBLE if you set the % of cards to be dealt as less than what ? 85% ?
I have a Jet to catch and I still have to pack up this laptop. I took some Grad courses in Stat but i am NOT a mathematician by any stretch. I no longer have the luxury of even proof reading this. Sorry.
I am told that Norm Wattenberger is very friendly and quick to reply with Technical Support.
I strongly urge you to contact him. I also think that he posts on occasion at BJ21.com