For instance, let's assume the game is 6D with 80% pen, we're 4 decks into the pack, the TC is +15 and only 12 aces have fallen from the pack. We have about 45 cards left 'till the cut card falls. Let's also assume in this situation that there is on average 16 play positions (including the D) worth of cards still left in the pack before the the cut card falls. Also, let's assume we are in a perfect world and the pit crew doesn't have any care at all about us being AP's or how many hands we play. We also have plenty of $ for a bk-roll. Now let's also assume we will be playing 1 on 1 with the D in any of the following manners while finishing out the shoe:
1) we can play one position with a total of eight hands to the D and eight hands to the player -or-
2) we can play three positions with a total of four hands to the D and twelve to the player -or-
3) we can play seven positions with a total of two hands to the D and fourteen to the player.
Which option would mathematically provide the highest return to the player? I assume that option #3 is best. More BJ's to the player???
