Lucky Ladies side bet in 2D

I come up with a true count of +7 to make the bet profitable.

Do I have this right? From a pure probability viewpoint:

QhQh = 2/104 * 1/103
XXmatch = 16 * (2/104 * 1/103)
20suited = 4 * ((8/104 * 7/103) + (2/104 * 2/103))
any20 = (32/104 * 31/103) + (8/104 * 8/103)

to simplify, skipping the common denominator and eliminating dups

QhQh = 2
XXmatch = 30
20suited = 88
any20 = 936
----------------
total = 1056 / 10712

Payouts:

QhQh = 250
XXmatch = 750
20suited = 880
any20 = 3744
----------------
total = 5624 = 52.5%