A ruined Picasso
From Picasso
The usual win, lose, push stats looks something like this (given for 1 deck): 43.8 win, 47.94 lose, 8.26 push. If one was never to double (play out you usual double as a hard hand and play out the splits as if the 'no double after split rule applied', how would the percentages be changed? I expect more wins and pushes and less loses, but how much more? If you could provide stats for 6 decks I would greatly appreciate.Regards, Picasso.
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Myself
From the above figures, one could incorrectly assume that it is normal to lose at a rate of---47.94 - 43.8 = 4.14%...A single deck game with the proper rules, is an exactly even game...I don't think you understand this game as completely as you think...Becuase the Casino takes your money when you bust, without risking anything, they have a built-in advantage of approx. 6.48%.
2.33% of this advantage is overcome because they pay you 3 to 2 for a blackjack...The remainder must be overcome by standing or hitting, doubling or splitting, when it is mathematically right to do so...Your question indicates that you do not understand this aspect of the game...By refusing to double down or split, you are actually telling the Casino---"thanks for the opportunity to reduce your built in advantage but I am not interested...I would rather lose my money faster and go home."
--will [something has gone wrong with my computer and the delete button is not functioning...I cannot eliminate any of my mistakes.]0ian