Depends on whether you mean TC or RC...
CharlieMosby,
First, let's make sure we're on the same page here. Typically, when we discuss the HiLo count, the "count" is the True Count (TC), which we calculate by dividing the Running Count (RC) by the number of decks remaining in the shoe.
Thus, if we're playing a 6D game and in the first deck we see 10 big cards (Aces & X's), 12 neutral cards (7's, 8's, and 9's), and 30 small cards (2's through 6's), then at that point the RC is
RC = 10*(-1) + 12*(0) + 30*(+1) = +20
The TC, though is found by dividing the RC by the remaining decks. In this case, the shoe still has 5 decks, so the TC at this point is
TC = +20/5 = +4.
That's a pretty good TC, so we'd probably put out a max bet (or two!).
The remaining five decks now contain 110 bigs, 60 neutrals, and 90 smalls. (Recall that 5 decks would normall contain 100 bigs, 60 neutrals, and 100 smalls.)
Let's say that the second deck in our game comes out exactly in proportion to the actual remaining shoe. in that case, those 52 cards will contain 110/5 = 22 bigs, 60/5 = 12 neutrals, and 90/5 = 18 smalls. What is the RC after this second deck has been played?
RC = +20 + 22*(-1) + 12*(0) + 18*(+1) = +16
So, as you stated, the "count" did indeed fall, since in this second deck we saw 4 more bigs than smalls.
On the other hand, what is the new TC? The RC is now +16, but the number of undealt decks is 4, so
T = +16/4 = +4.
Huh??? That's the same as we saw after the first deck was dealt. As I said above, we'd probably still be putting out our max bet at this point.
Of course, both of these statements are true:
1. The RC fell during the second deck, and
2. The TC remained the same.
What's I've done here is provide an example of the "True Count Theorem", which says that while the RC tends to zero, the TC tends to remain unchanged.
So, did we actually have an advantage during the second deck? Yes, we did: in those 52 cards, we say 4 more bigs than smalls, which corresponds to an increase of roughly 2% in our edge.
Just for fun, what would have happened if the second deck had come out with the "usual" distribution of bigs, neutrals, and smalls? Well, we would have seen 20 bigs, 12 neutrals, and 20 smalls, so the RC would have remained unchanged at +20. However, the TC would have increased to +20/4 = +5, indicating that we expect an even larger advantage during the remaining 4 decks.
Hope this helps!
Dog Hand