I live in Europe and I have played some times in one Casino that offers a strange option. You can put insurance not only against Ace, but also against 7, 8, 9, and 10s! (Insurance pays 2:1). E.g. if you have 20 and dealer shows 7, you can put insurance and if he caches 10(or figure), you win both ways! Your Insurance bet must be half of your original bet. I have read a similar situation on Wong�s Professional Blackjack about bust-out bet and I believe that this rule have the same advantage. Wong advises that the best option to play is a two � player team were one counts a normal count (hi-lo) and the other counts for the Insurance decisions (ten count, 10s: �2, other cards: +1, 24+ insurance).
But what I wonder is what is my advantage against the house for several (true?) counts? More simple, how much money must I bet? ( I bet 0.50 KELLY.) Do I have to bet according to hi-lo or according to 10 count? Also what is the better count of them for my playing decisions?
The rules of the house are: 6 decks
No hole card
Double after split
Resplit 4 times
Aces split once
Double any two cards
Early surrender but not against Ace
Stand soft 17