simultaneuos blackjacks
I'm sure if I thought about it enough, I could modify this clever formula for winning outright with a blackjack, and convert it to determine simultaneous blackjacks:
Odds of winning with a blackjack:
a * t * {1 - [2(a - 1) * (t - 1) / (n - 2) / (n - 3)]} / n / (n - 1)
where a = number of aces, t = number of tens, n = number of cards.
But it is Friday, so I will just use the lazy brute force method.
simultaneous blackjack in single deck -
A,T vs A,T ( 4/52) * (16/51) * ( 3/50) * (15/49) +
T,A vs A,T (16/52) * ( 4/51) * ( 3/50) * (15/49) +
A,T vs T,A ( 4/52) * (16/51) * (15/50) * ( 3/49) +
T,A vs T,A (16/52) * ( 4/51) * (15/50) * ( 3/49) = 0.001773
with 8 decks -
The same combinations
4*(128 * 127 * 32 * 31) / (416 * 415 * 414 *413) = 0.0021852
OR you push with a blackjack about 1 extra time per 2,500 hands with 8 decks vs single deck.