Halves Playing Variations

Hi Guys,
Can someone just varifiy that these playing variations are correct..i am using Ian Anderson's simpilified version of DS's Illustrious 18. I do plan to play halves with the doubled values.

1.Take Insurance if the TC is +3.3 (+6) or greater.
2. 12 vs. 2 � Stand if the TC is +3 (+6) or more.
3. 12 vs. 3 � Stand if the TC is +2 (+4) or more.
4. 12 vs. 4 � Hit on any negative RC.
5. 12 vs. 5 � Hit if the TC is �1 (-2) or less.
6. 12 vs. 6 � Hit any negative RC.
7. 16 vs. Ten � Stand on any positive RC.
8. 15 vs. Ten � Stand if the TC is +4 (+8) or more.
9. 13 vs. 2 � Hit on any negative RC.
10. 13 vs. 3 � Hit if the TC is �1 (-2) or less.
11. 9 vs. 2 � Hit on any negative RC.
12. 11 vs. Ace - Double if the TC is +1 (+2) or more.
13. 10 vs. Ace � Double if the TC is +4 (+8) or more.
14. 10 vs. Ten - Double if the TC is +4 (+8) or more.
15. 9 vs. 7 � Double if the TC is +3 (+6) or more.

Thxs.

http://www.cardcounter.com/indices/-21223210-1-2.htm

Hello, the indices shown from your link are different from those published in Stanford Wong's Prof. BJ table for Halves S17.

Why?

Thank you.

P.S. I think he used 4 decks for his table, but says that differences for 6 decks are negligible.

1. PBJ's indices iare for 4 decks

2. PBJ's indices are based on a count of values from -1 to +1.5, mine are based on -2 to +3. For example, if you are always truncating the values, then an index of 3.6 would be written in PBJA as 3, but when you double it, you get 7.2 which is truncated to 7 (not 6).

3. Wong's values are computed by simulation, mine are computed combinatorially (using Wong's software, PBJA).

But, if you use either set of indices (double the values from PBJ, or use the values from my site), the difference in EV is not going to be noticiable over the next 100,000 hands.

--Mayor

Hi,

If I use integers for the card values during the count,
i.e. -2, 1, 2, 2, 3, 2, 1, 0, -1, -2 instead of

-1, .5, 1, 1, 1.5, 1, .5, 0, -.5, -1

I can still use the indices in S. Wong's PB as long as I divide by 2 first and then the # of decks remaining (essentially counting half-decks remaining), right?

Thank you.