I know this is a newbie question, and I'm sure it's in BJ Attack somewhere (which I don't have here at work), but this question just came up from a friend and I forgot the answer. On a basic strategy level, I want to confirm that you split the 8,8 against a dealer 9, 10, A rather than surrender (late).
If you know, using a basic +/- true count (2-6, 10-A), when does your answer above change?
Thanks for your help!
6 deck, DAS, S17, Late Surrender.
1. Against 9 when the count is +7 or higher
2. Against T when the count is positive
SURRENDER BOTH in these two cases, otherwise, split.
for the 6 deck game he's inquiring about,
vs. 9 and 10: when count is +2 or higher
I would also take into consideration how much you have bet and the size of your bankroll. Your bet may be +2 or +7 in red green or black. This is a "lose less" play, not a "win more" play.
Take all things into consideration and make your own mind up...fast before they see you counting! grin
"I Surrender All"
6dks, DOA, DAS and LS
8-8 vs. 9
splitting = -.3892
..hitting = -.50571
.......LS = -.5000 BS = split
8-8 vs. 10
splitting = -.4748
..hitting = -.53536
.......LS = -.5000 BS = split
8-8 vs. A
splitting = -.36399
..hitting = -.51355
.......LS = -.5000 BS = split
If the Highlow TC is = or > 8 you shall not split 8-8 vs X, therefore surrender the hand.
Hope this helps
Z
