Has anyone calculated the 'house win' between a 4 deck and 6 deck BJ game using a simulation (or math). One must assume the same rules and identical playing strategies.
I'd like to see the math/ results.
Thankyou
Brian
I'll use UK rules for the purpose of this exercise as I'm based in the UK.
Dealer stands on soft 17
No surrender
Double on 9, 10, 11
split all pairs except 4, 5 and 10
allow multiple splits
allow double after split
dealers card is face up.
Thanks for the answer Don, but do you have any idea what causes the slight difference? Number of Blackjacks possible for the player maybe?
Thanks and regards,
Brian.
As number of decks increases, player edge decreases, although NOT linearly. Fewer naturals is part of it. Other considerations include: the composition of the hand for doubles and splits 9removing specific cards form the pack) affects SD odds more than multi.
The inverse of the floating advantage which means the results at horrible counts are further away from zero than are the equivalent great counts are more likely to arise in an arbitrary 52 cards in multideck than they are in the nonarbitrary cards in SD and less arbitrary cards in DD.
A combinatorial analyst that I know studied this once, and concluded that a 1/N relationship holds quit well for all probabilities that he looked at. Intuitively, the more decks the less variation. Every time you double the number of decks, you cut the variations in half. I believe Griffin talks about the 1/N characteristic somewhere, but I can't quote chapter/verse.