Hi guys, I read the KO book and came up with what I believe to be a pretty important question and a follow-up question to that. Here are some values that were suggested in the book: For a 6-deck game, use an initial running count of -20, a key count of -4, and place your max bet (10 units if using a 1-10 spread) at a count of +4 and above. For an 8-deck game, use an IRC of -28, a KC of -6, and a "max bet" count of +4 and above.
My question is: What is the theoretical (disregard standard deviation) percentage of the time the count should be at +4 and above for both the 6 and 8-deck games in a game employing let's say 75% penetration?
A follow-up to that is what exactly (or estimate, range, etc.) is your theoretical (again disregard standard deviations) win probability at a count of exactly +4 in both the 6 and 8-deck games using standard Vegas strip rules (dealer hits soft 17, double down after pair-splitting) at again 75% penetration? I know the win probability would be higher as the count goes higher than +4, but I'm mostly interested in the probability at the minimum count in which a 10-unit bet would be placed. Thanks for any input! I love this forum!