In the Revere Advance Point Count, is the true count found by dividing by the half decks left or by whole decks left? What is the multiplier used to multiply the true count to calculate my advantage over the house?
There really are two Revere Advanced Point Counts. One is called the 14-Count because the sum of the count values for low cards is 14. The other count includes the ace and has a sum of count values for low cards of 17. Both are balanced counts.
The true count divisor for both of the above counts is the number of half-decks remaining. The true count divisor for the High-Low Count is the number of full decks remaining. Each High-Low true count is worth about 0.5%. A typical game has a house advantage of about 0.5%, perhaps a little more with worsening rules. Therefore, a a High-Low true count of +2, the player has an advantage of nearly 0.5%.
The sum of the count values for low cards with High-Low is 5. Therefore, the value of each true count point for the 14 Count would be about (5/14) � 0.5 = 0.18% and the value of each true count point for the 14 Count would be about (5/17) � 0.5 = 0.15%, if the true count divisor were the number of full decks remaining. These numbers must be multiplied by 2 because the true count divisor were the number of half-decks remaining, i.e. they are about 0.36% and about 0.30%.
The Revere Advanced Point Counts are extremely difficult to use. Revere's playing indices were calculated more than forty years ago. Modern software, e.g. QFIT's CV-Data, probably produce more accurate index numbers.
Thank you very much for your fast response. Where can I find a chart for the number matrix when I deviate from basic strategy and the value of each card? If I don't round to half a deck I would have to use a multiplier of .36 to calculate my advantage over the house, is this correct. Would I have to also to double the assigned value to each card? For example if the 5 is valued at plus 4 does the value change to plus 8?
