The casino advertise a 99.95% RTP, in other words 0.05% house edge, in their information tab for this game. Im sure this number is based on x computed hands, however there seems to arise some situations that are unclear to me.
The conditions are:
- You only get to play 1 hand. After the hand, the deck will be shuffled
- Split as many times you want
- No RSA
- No peek at 10. If you double, or split, and lose to a BJ, you will lose both bets. However, if you catch a 21 you will push against a natural.
- If you catch 2 concecutive tens after splitting aces, dealer will open his hole card and not deal any more cards, whether it’s a pat hand or not, and immideately pay you.
Im looking for the optimal play in the following scenarios:
1: 11 vs 10
2: You split 77 vs 3 and catch a 5 on the first one, and an 8 on the second. Do you hit or stand with your hard 12?
3: 16 vs 10, when your hand is built up by 10-3-3. Remember to account for that catching a 5 will potentially tie a natural. In general Im curious whether it’s optimal or not to hit all 16s against 10, since there is a 1/13 chance that the dealer has an ace underneath.
4: 16 vs 9 when your hand is built up by 4425A or 6325
5: You split 88 vs A and receive a 3 on the first one, and 10 on the second. Do you double the 11?
There are plenty of «close call» situations like these that can arise after splitting, and I have failed to find appendices in the litterature. Im aware that these spots are super marginal, but I cant help myself thinking whether they are accounted for, or if the casino calculated the house edge based on a fixed basic strategy.
Any suggestions will be greatly appreciated.