6 decks, S17.
is it about 5% in occurrance to get 21 ??
what is the precise answer ?
How rare to get 4 hands in a row, either natural or 21 ?
[for BS player]
You draw to 21 about 5.5% of the time (including doubles). You get a natural 21 4.75% of the time. Together, you get a 21 just over 10% of the time (10.25%). (See BJA3, p. 50.)
To get four 21s in a row, for any designated four consecutive hands, is, therefore, .1025^4 = one chance in 9,066.
As with all such calculations, the event becomes much less rare when you play thousands upon thousands of hands, including thousands of such four-hand streaks. Sooner or later, you see just about everything.
Don
could i simply say that it is 0.3%.
and 21 vs natural bj =0.346% ??
Please state exactly the combination(s) of player hand(s) and dealer hand(s) that you are looking for.
Don
both BS player and dlr are 21 simultaneously at the same round.
1.34%
FYI, if you split and one of your hands ends up being 21, then I'm counting that as a round where you got 21.
