BJ CA

Hi,

I've made my CA available.

MGP

MGP,

I downloaded your program, unzipped it, and ran the "setup" application. I got a message from the Windows Installer Loader saying:

"This setup requires the .NET Framework version 1.1.4322. Please install the .NET Framework and run this setup again. The .NET Framework can be obtained from the web. Would you like to do this now?"

I clicked the "Yes" button, downloaded version 4 of .NET, installed it, and reran your "setup" app. I got the same message again. I tried rebooting the computer, but once again got the same message.

Does your application in fact require .NET Framework version 1.1.4322 EXACTLY?

Dog Hand

...the newer version(s) are probably already loaded in your computer via
ms updating service

BJayCobbson,

Thanks for your suggestion: that proved to be the case!

Indeed, I had to download and install a previous version of the .NET software.

For anyone else who has to find this version of .NET, here is the URL:

http://www.microsoft.com/download/en/details.aspx?displaylang=en&id=26

This is, in particular, "Microsoft .NET Framework Version 1.1 Redistributable Package".

I list this, because it was the THIRD .NET version 1.1 file I tried, AFTER trying version 4! :P

Hope this helps!

Dog Hand

P.S. And thanks, MGP, for making this program available!

... when you get some UDDER great program that requires .NET version 37.gxyz? U gonna switch back and forth every time? (Upgrade! Downgrade! Yesiree! Raise a cheer for ol' Billy!) How bout a dual boot? How bout you flap yer wings and squawk like a chicken?

There's just noooooo excuse for this nonsense. You know there USED to be this thing called backward compatibility. Do you think Microsloth'll EVER get an OS that works more'n half the time?

MGP,

Thanks for making available your BJCA to BJ community.

I used it a couple of times and I think it is great. But I am a little bit confused as to whether the probabilities are correct.

For example, in 6 deck game, if we have 7, 7 vs 8, the probability should be 0.00044 (0.044%) or (24/312)*(24/311)*(23/310). According to Strategies tab of MGP�s BJ CA Results Analysis, the number is 0.005725547142413. I can�t figure out what the meaning of this number is.

I could be at fault, or there could be an option I am not able to understand, or something else.

It will be very kind if you throw some light on this matter.

Kind regards,
Blackjack Rookie

If you take 0.005725547142413 and divide it by [(24/312)*(24/311)*(23/310)] the answer is almost exactly 13 (to something like 12 digits). So suppose you already know dealer has an 8 up, now what's the probability you will get a pair of sevens? Answer: 0.0057225...

Always happy to get proved wrong.

ETF

ET Fan,

Thanks for your attention.

You are absolutely right. If we remove an 8 from a 6 deck pack, then the probability of getting a pair of 7s is (24/311)*(23/310) or 0.0057255471424126. This number coincides completely with MGP�s 0.005725547142413.

Regards,

Blackjack Rookie