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Here is an example

Posted By: SOTSOG
Date: 25 Oct 01, 6:01 pm

In Response To: ok, but why? (sy)

First hand in a single deck game, you get an ace as your first card.
What are the chances that you get a 10 as your second card and get a blackjack? (16 tens / 51 remaining cards) = .3137 or about 1/3 the time.

Now in an eight deck game, first hand, you get an ace. What are your chances of getting a blackjack?
(128 tens / 415 remaining cars) = .3084 (slightly less than above.)

Notice that it is equally likely to get an ace as your first card in each game, but what happens after is slightly worse as each deck is added. This happens in a lot of different situations, suppose you have two small cards that add up to 11 and double down. The probabilty (with two small cards removed from play by being in your hand) of getting a 10 card for 21 on your double is slightly greater playing against a smaller number of decks.

If the dealer has four small cards and has to hit again, what are the chances of getting a big card and busting, as opposed to getting another small card for 21? Well, if he is using eight decks instead of 6, he has 2 more decks worth of small cards that he could possibly draw and make his hand.

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